Concepts Relating to Pythagoras' Example
The Square and the Root of Squares a Number
We have seen together that the square of a number is a repeating multiplication of a number twice. If a is a number then the square of a is a 2 . The following examples are quadratic forms:
5 2 = 5 x 5 = 25
[1945909] (- 3) 2 = (-3) x (-3) = 9
2 = 0,5 x 0,5 = 0, 25
[194590]
Then what is a square root? The square root of a number is a nonnegative number squared equal to that number. The square root of a number is the inverse of the square of a number. If y is the square of the number x ( y = x 2 ) then the number x is the square root of Number y = ( x = root y ). For example you can see the following:
√ 9 = 3
√ 16 = 4 √ 25 = 5
[1945907] - √ 9 = -3
√ ( -5) 2 = 5
Before learning about the Pythagorean proposition, you should first understand the extent of the square and the area of right triangles. Spacious Square The area of a Square s can be formulated into:
L = sxs = s
Suppose the square side length is 4 cm, then: [1945907]
L = sxs = 4 cm x 4 cm = 16 cm 2 [194590] The Area of the Right Triangle
Consider a square image composed of two segitigs A following elbow: [1945907]
From the picture above dapa t is known: [1945909]
Area of triangle ABD = 1/2 x Area Rectangular ABCD Area of triangle ABD = 1/2 x AB x AD
If the AB side is referred to as a base ( a ) And the AD side is referred to as tall (19459022) t ) then: Triangle area ABD = 1/2 x AB x AD Area of triangle ABD = 1/2 x Alas x Height Area of triangle ABD = 1/2 x a x t
] Suppose a triangle has a base of 9 cm and a height of 6 cm, then: Area of triangle = 1 / 2 x high base x [1945907] Area of triangle = 1/2 x 9 x 6
Area of triangle = 27 cm 2
[194590] That is some Concept Relating to Pythagoras's Pro before further studying the Pythagorean proposition you should well understand the concepts in Top because it will be useful in facilitating you later when learning about Pythagoras proposition. Hopefully this material is useful and you can understand it carefully
L = sxs = s
Suppose the square side length is 4 cm, then:
[1945907]
L = sxs = 4 cm x 4 cm = 16 cm 2 [194590]
The Area of the Right Triangle
Consider a square image composed of two segitigs A following elbow:
[1945907]
From the picture above dapa t is known:
[1945909]
Area of triangle ABD = 1/2 x Area Rectangular ABCD
Area of triangle ABD = 1/2 x AB x AD
If the AB side is referred to as a base ( a ) And the AD side is referred to as tall (19459022) t ) then:
Triangle area ABD = 1/2 x AB x AD
Area of triangle ABD = 1/2 x Alas x Height
Area of triangle ABD = 1/2 x a x t
] Suppose a triangle has a base of 9 cm and a height of 6 cm, then:
Area of triangle = 1 / 2 x high base x
[1945907] Area of triangle = 1/2 x 9 x 6
Area of triangle = 27 cm 2
[194590]
That is some Concept Relating to Pythagoras's Pro before further studying the Pythagorean proposition you should well understand the concepts in Top because it will be useful in facilitating you later when learning about Pythagoras proposition. Hopefully this material is useful and you can understand it carefully