Example Problem Area of a Circle and Discussion Complete
Example Problem Area of a Circle and Discussion - in a previous article Basic Mathematical Formulas provides a discussion of Sample Questions and discussion Circles Around . The material will be given on this occasion also still on a circle that is about examples of problems a wide circle of which will be accompanied by steps or a way to resolve the matter. Needless to linger longer let live we refer to with the description below:
Sample Questions and Discussion Area of a Circle Complete
Example Problem 1: [1945901million]
Calculate the area of a circle which has a radius of 15 cm!
Solved:
Given: r = 15 cm
Asked: area of a circle?
Answer: L = лr 2 [1945902million] = 3.14 x 15 x 15 = 706, 5 cm 2 [1945902million]
So the area of a circle is 706, 5 cm 2 [1945902million]
[1945901million]
Calculate the area of a circle which has a radius of 15 cm!
Solved:
Given: r = 15 cm
Asked: area of a circle?
Answer: L = лr 2 [1945902million] = 3.14 x 15 x 15 = 706, 5 cm 2 [1945902million]
So the area of a circle is 706, 5 cm 2 [1945902million]
[1945901million]
Example Problem 2: [1945901million]
A circle has an area of 1,386 cm 2 [1945902million]. Calculate the radius of the circle!
A circle has an area of 1,386 cm 2 [1945902million]. Calculate the radius of the circle!
Solved:
Given: L = 1,386 cm 2 [1945902million]
Asked: fingers?
Answer:
L = лr 2 [1945902million]
1,386 cm 2 [1945902million] = 22 / 7 x r2
r2 = 1,386 cm2 x 7/22
r2 = 441 cm 2 [1945902million]
r = √441 = 21 cm
so, radius of the circle is 21 cm
Asked: fingers?
Answer:
L = лr 2 [1945902million]
1,386 cm 2 [1945902million] = 22 / 7 x r2
r2 = 1,386 cm2 x 7/22
r2 = 441 cm 2 [1945902million]
r = √441 = 21 cm
so, radius of the circle is 21 cm
Example Problem 3:
mother made coasters circular diameter of 4 cm. coasters made of patchwork. Determine the area of the base the glass!
Solved:
Given: r = 2 cm
Asked: area of a circle?
Answer: L = лr 2 [1945902million] = 3.14 x 2 x 2 = 12.56 cm 2 [1945902million]
So the area of a circle is 12.56 cm 2 [1945902million]
Example Problem 4: [1945901million]
A circular park with a radius of 14 meters will be planted with grass. Price grass is RP. 5000,00 / m2. Calculate the costs to buy the grass!
Solved:
Given: r = 14 m, the price of grass = RP. 5000,00 / m 2 [1945902million].
Asked: cost?
Answer: [1945901million]
Costs incurred = broad lawn garden x price
Size park = лr 2 [1945902million] = 22/7 x 14 x 14 = 616 m 2 [1945902million].
costs = 616 x RP. 5000,00 = Rp. 3,080,000.00
So the cost of Rp. 3,080,000.00.
Sample Problem 5: [1945901million]
A circular-shaped pool has a 7 meter radius, surrounding the park is made walkway with a width of 2 meters. Determine the area of the path!
Solved:
Given: r = 7 m, width of the road = 2m.
Asked: Broad Street?
Answer:
Size path = (wide roads and ponds) - spacious pool
Size road and pond = Size large circle = лr 2 [1945902million] = 3:14 x (7 + 2) x (7 + 2) = 254.34 m 2 [1945902million].
Size pool = лr 2 [1945902million] = 22/7 x 7 x 7 = 154 m 2 [1945902million]
mother made coasters circular diameter of 4 cm. coasters made of patchwork. Determine the area of the base the glass!
Solved:
Given: r = 2 cm
Asked: area of a circle?
Answer: L = лr 2 [1945902million] = 3.14 x 2 x 2 = 12.56 cm 2 [1945902million]
So the area of a circle is 12.56 cm 2 [1945902million]
Example Problem 4: [1945901million]
A circular park with a radius of 14 meters will be planted with grass. Price grass is RP. 5000,00 / m2. Calculate the costs to buy the grass!
Solved:
Given: r = 14 m, the price of grass = RP. 5000,00 / m 2 [1945902million].
Asked: cost?
Answer: [1945901million]
Costs incurred = broad lawn garden x price
Size park = лr 2 [1945902million] = 22/7 x 14 x 14 = 616 m 2 [1945902million].
costs = 616 x RP. 5000,00 = Rp. 3,080,000.00
So the cost of Rp. 3,080,000.00.
Sample Problem 5: [1945901million]
A circular-shaped pool has a 7 meter radius, surrounding the park is made walkway with a width of 2 meters. Determine the area of the path!
Solved:
Given: r = 7 m, width of the road = 2m.
Asked: Broad Street?
Answer:
Size path = (wide roads and ponds) - spacious pool
Size road and pond = Size large circle = лr 2 [1945902million] = 3:14 x (7 + 2) x (7 + 2) = 254.34 m 2 [1945902million].
Size pool = лr 2 [1945902million] = 22/7 x 7 x 7 = 154 m 2 [1945902million]
So little discussion we can bring about Example Problem area of a Circle and discussion Complete hopefully what I have described above can help you all to understand how to solve problems related to materials about the area of a circle and equations. Thank you for listening to this paper well, see you in the discussion of the question,