How to Solve Problems of SPLDV with Elimination Method [1945900] Resolving the SPLDV Problem with the Elimination Method - On the discussion of Formulas Basic Mathematics before we have learned together about how to solve SPLDV problem by substitution method . This time we will discuss other methods that can also be used to work on SPLDV problems called the Elimination method. What is meant by the elimination method is to eliminate or eliminate any of the variables and variables to be eliminated must have the same coefficients. If the coefficient of variables is not the same then you must multiply one equation with a certain constant so that there will be variables that have the same coefficients. To understand this method, let's just look at the example of the problem and the solution below: [1945907] Sample SPLDV Problem and Its Solution by Elimination Method [1945904] Example Problem 1: There are two equations, ie 2x + y = 8 and x - y = 10 with x, y R. Find the set of solutions of the system of equations by the method of elimination! Solution: From both equations, you can see the same coefficients possessed by variable y. Therefore, this y variable can we eliminate by summing. Thus the value of x can be determined in the following way: 2x + y = 8 x - y = 10 + 3x = 18 X = 6 2x + y = 8 | X 1 | 2x + y = 8 x - y = 10 | X 2 | 2x - 2y = 20 - 3y = -12 y = -4 Hence, the set The solution of the above equation system is (6, 4). [1945909] [1945909] Mixed Method In addition to using graphical methods, substitution methods, and methods of elimination, the system of equations Linear can also be solved by using a mixed method which is a combination of substitution methods with the method of elimination. The trick is to complete SPLDV with the method of elimination first and then proceed with substitution method. Consider the following example to understand how: Example Problem 2: Determine the set of settlements From the system of equations 2x + y = 5 and 3x - 2y = 11 where x, y R.

Solution:
2x + y = 5 ........ (1)
3x - 2y = 11 .... (2)

Of the two equations above are not found coefficients of the same variable so that one of the coefficients of variables must be equated in advance by multiplying both equations With a number. For example we want to equate the coefficient of variable x then the first equation is multiplied by 3 and the second equation is multiplied by 2.

2x + y = 5 | X3 | ó 6x + 3y = 15
3x - 2y = 11 | X2 | - 6x - 4y = 22 -
7y = -7
Y = - 1

Then the result can we substitute into one equation. Suppose the first equation, so obtained:

2x + y = 5
2x -1 = 5
2x = 5 + 1
x = 3

Thus, the set of solutions of the system of linear equations is (3, -1)
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So much of the full discussion we can tell you all about Resolving the SPLDV Problem with the Elimination Method You can make it easier to solve the questions about the system of linear equations of two variables. Until re-encounter in the discussion of the following questions.
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