Sample Questions and Discussion Systems of Linear Equations Two Variables
Sample Questions and Discussion Systems of Linear Equations Two Variables - are you already understand what the purpose of the SPLDV? If not, we suggest you first read the material in advance of Explanation Method of Substitution and Elimination Systems of Linear Equations Two Variables for discussion of which will be provided by Mathematical Formulas Basic this time associated with such materials. if you have read and understand the concepts in it, let's let our direct same as studying examples of problems that exist below:
Example Problem systems of Linear Equations Two Variables and Discussion
Example Problem 1
Specify the completion of SPLDV following with substitution method:
x + y = 8
2x + 3y = 19
Answer: [1945901million]
x + y = 8 .... (1)
2x + 3y = 19 ... (2)
x + y = 8
x = 8- y
Specify the completion of SPLDV following with substitution method:
x + y = 8
2x + 3y = 19
Answer: [1945901million]
x + y = 8 .... (1)
2x + 3y = 19 ... (2)
x + y = 8
x = 8- y
Subtitusikan x = y - 8 to in equation 2 [1945901million]
[1945901million]
2 (8- y) + 3y = 19
16 - 2y + 3y = 19
16 + y = 19
y = 3
Subtitusikan y = 3 in equation 1 [1945901million]
2 (8- y) + 3y = 19
16 - 2y + 3y = 19
16 + y = 19
y = 3
Subtitusikan y = 3 in equation 1 [1945901million]
[1945901million]
x + 3 = 8
x = 5
Thus, the completion of SPLDV is x = 5 and y = 3
Example Problem 2 [1945901million]
Specify the completion of SPLDV following the elimination method :
2x - y = 7
x + 2y = 1
Answer: [1945901million]
The elimination of x [1945901million]
2x - y = 7 | x1 -> [1945901million] 2x - y = 7 ... (3)
x + 2y = 1 | x2 -> [1945901million] 2x - 4y = 2 ... (4)
2x - y = 7
x + 2y = 1 -
-5y = 5
y = -1
Elimination y [1945901million]
2x - y = 7 | x2 -> [1945901million] 4x - 2y = 14 ... (5)
x + 2y = 1 | x1 -> [1945901million] x + 2y = 1 ... (6)
4x - 2y = 14
x - 2y = 1 -
5x = 15
x = 3
Thus, the completion of the SPLDV is x = 3 and y = -1
Example Problem 3 [1945901million]
Specify the completion of the following SPLDV with mixed method:
x + y = -5
x - 2y = 5
replied: [1945901million]
the elimination of x [1945901million]
x + y = -5
x - 2y = 5 -
3y = -9
y = -3
substitution y [1945901million]
x + (-3) = -5
x = -2
x + 3 = 8
x = 5
Thus, the completion of SPLDV is x = 5 and y = 3
Example Problem 2 [1945901million]
Specify the completion of SPLDV following the elimination method :
2x - y = 7
x + 2y = 1
Answer: [1945901million]
The elimination of x [1945901million]
2x - y = 7 | x1 -> [1945901million] 2x - y = 7 ... (3)
x + 2y = 1 | x2 -> [1945901million] 2x - 4y = 2 ... (4)
2x - y = 7
x + 2y = 1 -
-5y = 5
y = -1
Elimination y [1945901million]
2x - y = 7 | x2 -> [1945901million] 4x - 2y = 14 ... (5)
x + 2y = 1 | x1 -> [1945901million] x + 2y = 1 ... (6)
4x - 2y = 14
x - 2y = 1 -
5x = 15
x = 3
Thus, the completion of the SPLDV is x = 3 and y = -1
Example Problem 3 [1945901million]
Specify the completion of the following SPLDV with mixed method:
x + y = -5
x - 2y = 5
replied: [1945901million]
the elimination of x [1945901million]
x + y = -5
x - 2y = 5 -
3y = -9
y = -3
substitution y [1945901million]
x + (-3) = -5
x = -2
Thus, the completion of the SPLDV is x = -2 and y = -3
Example Problem 4 [1945901million]
Melly age 7 years younger than the age Ayu. The number of them was 43 years of age. Determine the age of each of them!
Answer:
Suppose age melly = x and age ayu = y, then
y - x = 7 ... (1)
y + x = 43 ... (2)
y = 7 + x
subtitusikan y = 7 + x into equation 2 [1945901million]
7 + x + x = 43
7 + 2x = 43
2x = 36
x = 18
y = 7 + 18 = 25
so, melly age is 18 years and 25 years of age ayu.
Sample Problem 5
a garden has a length of 8 meters longer than its width. The park circumference is 44 m. specify the area of the park!
Answer: Size park = pxl
P = length of the park
L = width of the park
The mathematical model:
P = 8 + l
k = 2p + 2l
2 (8 + l) + 2l = 44
16 + 2l + 2l = 44
16 + 4l = 44
4l = 28
l = 7
a garden has a length of 8 meters longer than its width. The park circumference is 44 m. specify the area of the park!
Answer: Size park = pxl
P = length of the park
L = width of the park
The mathematical model:
P = 8 + l
k = 2p + 2l
2 (8 + l) + 2l = 44
16 + 2l + 2l = 44
16 + 4l = 44
4l = 28
l = 7
P = 7 + 8 = 15
Size = 7 x 15 = 105 m [1945902million] 2
Thus, the area of the park is 105 m [1945902million] 2
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