Example of Problems of Cultivation and Conflict Upon a Flatter and Its Solution

The Basic Mathematical Formula has already given material reviews Concerning The Cultivation and Conflict of Worshiping Mathematics . Well, to deepen your understanding of the material, here we will provide some examples of questions you can use to practice at home. In each case will be given an explanation of how to solve it. But for some other questions you have to do it yourself or it could be accompanied by your parents or brother to ask if you find difficulties in understanding how to solve the given problem. Let's just look at the first example of the problem:

Sample Problems of Cul- ture and Conflict Build Flat [1945909] [1945907]

Sample Problem 1:

Notice the drawing of the two rhinos below, whether the two constructs can be expressed congruently

Solution:

In order to answer that question, you must recall the properties of the flat wake Liki by rhombus, that is:

a. All sides are equal in length and in parallel pairs.

b. The facing angles are equally large and divided equally.

In the rhombic ABCD above, it is known that AB = BC = CD = AD = 6 cm,

Angle A = angle C = 40 ⁰ and angle B = angle D = 140 ⁰ (opposite corners)

In the above EFGH rhub, it is known that EF = FG = GH = EH = 6 cm,

Angle E = angle G = 40 ⁰ and angle F = angle H = 140 ⁰

[1945907] ]

From the description can be obtained:

AB / EF = BC / FG = CD / GF = AD = EH = 1

angle A = angle C = Angle E = angle G = 40 0

angle B = angle D = angle F = angle H = 140

Since the corresponding sides have equal lengths and corresponding angles, ABCD And EFGH can be said to be congruent.

Example Problem 2:

Notice the glide- (19459013)

Settlement: [1945909] [194590]] [194590]

The kite has the same pair of opposite corners which we can use to find the unknown angles of magnitude on a kite.

For ABCD kites:

Angle D = Angle B = 110 ⁰ and The angle C = 360 ⁰

then the angle C = 360 ⁰ - (110 + 110 + 80) ⁰

For the EFGH kite: [1945907] Angle H = Angle F = 110 ⁰ and angle G = 80 ⁰

] then the angle E = 360 ⁰ - (110 + 110 + 80) ⁰ = 60 0

Thus we can conclude that:

Angle A = angle E, angle B = angle F, angle C = angle G, and angle D = angle H. and turns corresponding angles on both kites are equal

For ABCD kites, it is known that CD = BC = 6 cm and AB = AD = 9 cm

For the EFGH kites, it is known that GH = FG = 4 cm and EH = EF = 6 cm

So that can be obtained: BC / FG = DC / GH = 6/4 = 3/2

AD / EH = AB / EF = 9/6 = 3/2

Since the corners are the same And the corresponding side-to-side ratios we can conclude that the ABCD kite is similar to EFGH.

[1

If you are already Understand with the explanation of the above problem, it is time you practice to work on the questions below:

Problem Exercise 1:

Notice the following picture:

Are trapezoidal ABCD and ESPGH trapezoid unfold? Explain your answer!

Problem Exercise 2:

a. Is the KLMN rectangle parallel to the PQRS rectangle?

b. Is the KLMN rectangle congruent with the PQRS rectangle?

Problem 3:

Among the following builds, which is certainly true?

a. Two squares

b. Two samakaki triangles

c. Two equilateral triangles

d. Two right-angled triangles

e. Two diamonds

f. Two orderly sides

g. Two circles

h. Two kites

Now that's some The example of the Cul- ture And the Conflict of Conflict which you can try to do to test your ability on the material. Continue to practice and keep the spirit of learning so that you can work on issues of camaraderie and congruence to wake flat with other forms. Thank you for listening to this material until the end, see you again.

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